Heading Level 1
Heading Level 2
Heading Level 3
Heading Level 4
Heading Level 5
Heading Level 6
Basic Text Formatting
This is regular paragraph text with bold text and italic text. You can also have bold and italic text together. Here’s some strikethrough text.
Links and References
This is a link to Jekyll’s website
Lists
Unordered List
- Item 1
- Item 2
- Nested item 2.1
- Nested item 2.2
- Item 3
Ordered List
- First item
- Second item
- Nested item 2.1
- Nested item 2.2
- Third item
Blockquotes
This is a blockquote. It can span multiple lines.rrrrr
This is a nested blockquote.
Life’s but a walking shadow, a poor player, that struts and frets his hour upon the stage, and then is heard no more. It is a tale told by an idiot, full of sound and fury, signifying nothing. — William Shakespeare, “Macbeth,” Act V, Scene V
读书不觉已春深,一寸光阴一寸金。 —— 王贞白
Code
Inline code looks like this.
Code Blocks with Syntax Highlighting
def print_hi(name)
puts "Hi, #{name}"
end
print_hi('Tom')
#=> prints 'Hi, Tom' to STDOUT.
function sayHello(name) {
console.log(`Hello, ${name}!`);
}
sayHello('World');
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
result = factorial(5)
print(f"The factorial of 5 is {result}")
# Output: The factorial of 5 is 120
#include <stdio.h>
int main() {
int n = 5;
int factorial = 1;
for(int i = 1; i <= n; i++) {
factorial *= i;
}
printf("The factorial of %d is %d\n", n, factorial);
return 0;
}
#include <iostream>
using namespace std;
int factorial(int n) {
if (n == 0)
return 1;
else
return n * factorial(n-1);
}
int main() {
int n = 5;
cout << "The factorial of " << n << " is " << factorial(n) << endl;
return 0;
}
Tables
| Header 1 | Header 2 | Header 3 |
|---|---|---|
| Cell 1,1 | Cell 1,2 | Cell 1,3 |
| Cell 2,1 | Cell 2,2 | Cell 2,3 |
| Cell 3,1 | Cell 3,2 | Cell 3,3 |
Horizontal Rule
Images

Definition Lists
- Term 1
- Definition 1
- Term 2
- Definition 2a
- Definition 2b
Highlight Test
This is a paragraph with a ==highlighted text== using Markdown.
This is highlighted using HTML mark tag
Math (if you’re using MathJax)
When $a \ne 0$, there are two solutions to $ax^2 + bx + c = 0$ and they are
\[x = {-b \pm \sqrt{b^2-4ac} \over 2a}\]More text continues here…
Footnotes
Here’s a sentence with a footnote. 1
Task Lists
- Completed task
- Incomplete task
- Another incomplete task
Emoji (if supported)
![]()
Custom HTML
End of Test
This concludes the Markdown test file.
-
This is the footnote. ↩